修复默认地址与用户搜索问题
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@@ -27,6 +27,8 @@ public class UserPageReqVO extends PageParam {
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@Schema(description = "手机号码")
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private String mobile;
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private String phone;
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@Schema(description = "添加时间")
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@DateTimeFormat(pattern = FORMAT_YEAR_MONTH_DAY_HOUR_MINUTE_SECOND)
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private LocalDateTime[] createTime;
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+1
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@@ -36,7 +36,7 @@ public interface MemberUserMapper extends BaseMapperX<MemberUserDO> {
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.likeIfPresent(MemberUserDO::getUsername, reqVO.getUsername())
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.likeIfPresent(MemberUserDO::getRealName, reqVO.getRealName())
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.likeIfPresent(MemberUserDO::getNickname, reqVO.getNickname())
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.eqIfPresent(MemberUserDO::getMobile, reqVO.getMobile())
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.likeIfPresent(MemberUserDO::getMobile, reqVO.getPhone())
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.betweenIfPresent(MemberUserDO::getCreateTime, reqVO.getCreateTime())
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.orderByDesc(MemberUserDO::getId));
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}
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+4
@@ -43,6 +43,10 @@ public class AppUserAddressServiceImpl extends ServiceImpl<UserAddressMapper,Use
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*/
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@Override
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public Long addAndEdit(Long uid, AppAddressParam param){
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if(ShopCommonEnum.ENABLE_1.getValue().equals(param.getIsDefault())){
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userAddressMapper.update(UserAddressDO.builder().isDefault(ShopCommonEnum.DEFAULT_0.getValue()).build(),
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new LambdaQueryWrapper<UserAddressDO>().eq(UserAddressDO::getUid,uid));
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}
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UserAddressDO userAddress = UserAddressDO.builder()
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.address(param.getAddress())
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.detail(param.getDetail())
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